Extract substring using perl regex

Question

How to extract substring using perl regex for following?

Input: firstString123456lastString
Output: firstString

Input: first$String 123456 last@String
Output: first$String

Something similar to

echo "firstString123456lastString" | sed -e "s|\([a-z]*\)[0-9].*|\1|"

Return substring that comes before any number with in the input string — Murali Mopuru
– Murali Mopuru, Commented Nov 27, 2014 at 4:52

Avinash Raj · Accepted Answer · 2014-11-26 10:44:56Z

1

Through sed,

$ echo 'firstString123456lastString' | sed 's/^\([^0-9 ]*\).*/\1/'
firstString
$ echo 'first$String 123456 last@String' | sed 's/^\([^0-9 ]*\).*/\1/'
first$String

Explanation:

^ Asserts that we are at the start.
[^0-9 ]* Negated character class which matches any character but not of numbers or space zero or more times.
([^0-9 ]*) Matched characters are captured by the group index 1.

edited Nov 26, 2014 at 10:44

answered Nov 26, 2014 at 10:37

Avinash Raj

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Joe · Accepted Answer · 2015-12-12 20:34:38Z

0

$ echo "firstString123456lastString" | perl -pe 's/^([a-zA-Z]*)\d.*/$1/'
firstString

$ echo 'first$String 123456 last@String' | perl -pe 's/^([^\d\s]*).*/$1/'
first$String

answered Dec 12, 2015 at 20:34

Joe

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