I am using this code for a X 'n' O file. What I have done is an IF statement with NOT option but using || operator I want to define multiple choices. That states the problem here. Please help me. Code below:
if (!xslot=="1" || !xslot=="2" || !xslot=="3" || !xslot=="4" || !xslot=="5" || !xslot=="6" || !xslot=="7" || !xslot=="8" || !xslot=="9") {
alert("Please enter a valid slot number from 1 to 9.");
}
Great thanks to anyone who helps me.
You can use indexOf(), it returns the first index at which a given element can be found in the array, or -1 if it is not present.
var arr = [];
for (var i = 1; i < 10; i++) {
arr.push(i);
}
var xslot = 15;
if (arr.indexOf(xslot) == -1) {
alert('xslot is not in range')
};You could also use $.inArray()
If you're only checking a number in range, try this snippet:
var i_xslot = parseInt(xslot, 10);
if (i_xslot < 1 || i_xslot > 9) {
alert("Please enter a valid slot number from 1 to 9.");
}
Since you want to work with numbers, treat the input as a number :
if(+xslot < 1 || +xslot > 9)
alert("Please enter a valid slot number from 1 to 9.");
+xslot force the conversion to an int of xslot...
