Regular expression parameters string

Question

How i can cut in my string this

&ertert&User=3435&5454&Parameters=asasasa

I want to see only 3435 I have this already , but i don't know how to cut only 3435

&User=(\d+)

Do you want specifically 3435, or do you want the first set of numbers? — user3310334
– user3310334, Commented Nov 28, 2014 at 8:16
What you did should work. How do you retrieve the result at the end ? Usually, the result of a regex matching is an array with first element the entire matched pattern and next all the captured groups. — tomaoq
– tomaoq, Commented Nov 28, 2014 at 8:18
yes i want only numbers or text after &User=, but only that that text until next &. For example &ertert&User=3435&LALAL&Parameters=asasasa only 3435 , but this could be also text not just numbers — John
– John, Commented Nov 28, 2014 at 8:22

Amit Joki · Accepted Answer · 2014-11-28 08:27:36Z

3

You could use lookaheads and behinds provided you've got their support as you've not mentioned the language.

/(?<=User=).+?(?=&)/

The above regex will only match 3435

The lookbehind (?<=User=) is to make sure the number what we are trying to match is preceded with the token provided in the look behind. In this case User=

edited Nov 28, 2014 at 8:27

answered Nov 28, 2014 at 8:16

Amit Joki

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3 Comments

John Over a year ago

doesn't work. I need this for ms sql .For example &ertert&User=3435&LALAL&Parameters=asasasa only 3435 , but this could be also text not just numbers

John Over a year ago

try here regexr.com. Put my string and try yours regex. For me it doesn't work

Avinash Raj Over a year ago

@John what's wrong with printing the group index 1?

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