Loop to search and display certain parts of array Java

Question

I'm having trouble making a loop or even if statement to search through an array and then if it returns the value of it, it displays it along with the word before and after.

For example:

String Criminals[] = {
    "John Doe, Theft, 1990",
    "Marry Al, Arson, 1970",
    "Sal Don, Theft, 1961"
};

it searchs for theft and then it will get the name and date as well, and find the rest if there are any: and the output in this case would be:

Results (2):

John Doe, Theft, 1990
Sal Don, Theft, 1961

You can use HashMap. You can specify its value and key to find it. — Vighanesh Gursale
– Vighanesh Gursale, Commented Nov 28, 2014 at 19:10
Looks like a Custom class instead of a String will help you a lot — Marco Acierno
– Marco Acierno, Commented Nov 28, 2014 at 19:13

Boann · Accepted Answer · 2014-11-28 19:10:09Z

1

for loop to iterate the array and String.contains to see if items contain your search term. The only vaguely interesting part is converting all the strings involved to a particular letter case; e.g., lower case, in order to make the search case insensitive.

String searchTerm = ...;
searchTerm = searchTerm.toLowerCase();
for (String s : Criminals) { // loop
    if (s.toLowerCase().contains(searchTerm)) { // find
        System.out.println(s); // display
    }
}

answered Nov 28, 2014 at 19:10

Boann

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1 Comment

Taj Melic Over a year ago

Thanks so much! Worked perfectly.

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