Creating an array with a variable

Question

I have the following code:

#include <iostream>

using namespace std;

int main()
{
   unsigned int endx = 5;
   unsigned int endy = 5;
   unsigned int endz = 5;

   int Matrix[endx+1][endy+1][endz+1] = {};

   return 0;
}

I get

error C2057: expected constant expression

Ok, how can I create the Matrix like shown in the code without vectors or dynamic allocated array?

outlyer · Accepted Answer · 2014-12-02 00:49:06Z

2

As the error says, you need constant expressions to define array/matrix sizes; in that example, make integers const and it will compile.

const unsigned int endx = 5;
const unsigned int endy = 5;
const unsigned int endz = 5;

If you don't want dynamically allocated arrays or vectors, then you'll have to know the exact array size beforehand.

answered Dec 2, 2014 at 0:49

outlyer

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Comments

Jay Miller · Accepted Answer · 2014-12-02 00:47:22Z

2

Arrays require constants when creating them. In this code, just making your end* variables const unsigned int should do it.

answered Dec 2, 2014 at 0:47

Jay Miller

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2 Comments

hasan Over a year ago

he do plus one: endx+1

Jay Miller Over a year ago

Yes, if endx is type const unsigned int then endx + 1 is still a constant. It works...try it.

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