I have a field in a MongoDB Collection like:
{
place = ['London','Paris','New York']
}
I need a query that will return only that particular entry of the array, where a specific character occurs. For Example, I want to search for the terms having the letter 'o'(case-insensitive) in them. It should just return 'London' and 'New York'.
I tried db.cities.find({"place":/o/i}), but it returns the whole array.
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2 Answers
You'll need to $unwind using an aggregate query, then match.
db.cities.aggregate([ { $unwind:'$place' }, { $match: { place : {$regex: /o/i } } } ])
Comments
In simple you find with $regex below query will work without aggregation
db.collectionName.find({ place : {$regex: /o/i } })
