How does one overload methods in typescript? [duplicate]

Question

How does one overload methods in typed script. Given the following code, I have a class which implements an interface. The interface has 'polymorhpic' methods but I cant seem to implement them - getting the error "duplicate identifyer 'MyMethod'".

export class IService {

   MyMethod(): string;
   MyMethod(value: string): number;

}

export class MyService implements IService {

   MyMethod(): string { return "hello world;" } 
   MyMethod(value: string): number { return 1; }     

}

As i know it there is not possible to do that in typescript. You can create a single method with optional parameter MyMethod(param: string = ""): string { if (param == "") return 1; else return "hello world"; } — Raziza O
– Raziza O, Commented Dec 3, 2014 at 12:57

MarzSocks · Accepted Answer · 2014-12-03 13:21:01Z

1

OK I've managed to solve the problem, you do it like this, (note that the actual implementation of MyMethod covers all input and return types):

export class IService {

   MyMethod(): string;
   MyMethod(value: string): number;

}

export class MyService implements IService {

   MyMethod(): string;
   MyMethod(value: string): number;
   MyMethod(value: string = ""): any { if(value != "") return 1 else return "hello world"; }     

}

answered Dec 3, 2014 at 13:21

MarzSocks

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