Returning array from JQuery For Each Loop

Question

I'm trying to return an array of some simple information from a for each loop without success. Here is the code I'm using in two different functions.

function getUser(uname, callback) {
var u = "http://itsuite.it.brighton.ac.uk/john10/ci227/a1/whois.php?username=" + uname;
return $.get(uname, {}, callback);
}

function parseUserInfo(usrname) {
getUser(usrname, function(data) {
    var x = new Array();
    $(this).find("user").each(function() {
        x['username'] = $(this).find("username").text();
        x['firstname'] = $(this).find("firstname").text();
        x['surname'] = $(this).find("surname").text();
        return x;
    }
}
}

All I'm getting when I use it like this:

var dat = parseUserInfo("guest");

Is Undefined when using the console.log(dat) so could someone tell me where I'm going wrong here?

Many Thanks! Oh Btw I have looked at other solutions on here and elsewhere but as yet cannot find anything that works for me, so please no 'this thread is a duplicate' or 'its been answered here' links coz that will put me back to square one and make asking this question pointless!

Chirag Bhatia - chirag64 · Accepted Answer · 2014-12-03 17:11:11Z

2

x is getting returned to the getUser() function. You need to define and return x outside the getUser() in parseUserInfo().

So your code should look something like this:

function parseUserInfo(usrname) {
  var x = new Array();
  getUser(usrname, function(data) {
    $(this).find("user").each(function() {
      x['username'] = $(this).find("username").text();
      x['firstname'] = $(this).find("firstname").text();
      x['surname'] = $(this).find("surname").text();
    });
  });
  return x;
}

edited Dec 3, 2014 at 17:11

answered Dec 3, 2014 at 16:29

Chirag Bhatia - chirag64

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7 Comments

skobaljic Over a year ago

Correct, if you use return false instead of return x it would just break $.each loop.

Geordie Dave Over a year ago

Yes but how do I do that? This is what my question was about.

Geordie Dave Over a year ago

Unfortunately that didn't work, in your answer none of the functions are closed off properly with the ); at the end and in each point I tried putting the return x; after it, I just got returned with parseUserInfo is undefined, could you please modify the code to how it should look? - Further to this, I closed the getUser and .each functions off myself and still got same result, aside from one but returned an empty array. Console logged: []

Chirag Bhatia - chirag64 Over a year ago

I've solved the syntax errors by closing the functions. Try putting a console.log(data); between the 3rd and 4th line of my code. Lets see what, if any data you're getting from the $.get() request.

Geordie Dave Over a year ago

Undefined and [] on separate lines are all the console is giving, this is a nightmare, I don't understand how it is so hard to return an array of the data.

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