How to convert input as boolean type and use it in if and else statement?

Question

x = bool(input ( "Write True or False\n"))

if  x is True :
  print("its true")
elif x is False :
    print ("its false")

when I write True or False I always get "its true". i want the program to say "its false" when i type False.

I cannot think of any type that will fall into your else case. — Cory Kramer
– Cory Kramer, Commented Dec 3, 2014 at 16:47
Depending how specific you want to be keeping it a string and checking against that string may be the way to go. — user2097159
– user2097159, Commented Dec 3, 2014 at 16:48
Is there a reason you don't want to say if x == "True"? In python, an empty String will be False, but any String will text in it will evaluate to True. — ekrah
– ekrah, Commented Dec 3, 2014 at 16:48

Cory Kramer · Accepted Answer · 2014-12-03 16:48:55Z

1

You'll have a problem with converting to bool because technically any non-empty string will evaluate to True

>>> bool('True')
True
>>> bool('False')
True
>>> bool('')
False

You can use ast.literal_eval though

>>> from ast import literal_eval
>>> literal_eval('True')
True
>>> literal_eval('False')
False

Otherwise you'll have to compare the actual strings themselves

x = input("Write True or False\n")

if x in ('True', 'true'):
  print("its true")
elif x in ('False', 'false'):
    print ("its false")
else:
    print("don't know what that is")

answered Dec 3, 2014 at 16:48

Cory Kramer

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Comments

rlms · Accepted Answer · 2014-12-03 16:51:19Z

0

I'd just compare the strings:

x = input("Write True or False\n")

if x == "True":
  print("its true")
elif x == "False":
    print ("its false")
else:
    print("don't know what that is")

answered Dec 3, 2014 at 16:51

rlms

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