1

if I have a string like 'foo(bar)', with the following code i can almost parse it the way i want:

$results = array();
preg_match( "/\w*(?=(\(.*\))?)/", 'foo(bar)', &$results );
print_r($results);

/*    
Array
(
    [0] => foo
    [1] => (bar)
)
*/

How can I modify the regex to have bar instead of (bar)? Thanks

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  • Is there any particular reason why you are using look ahead? Normally /(\w+)\((\w+)\)/ would suffice. Commented Apr 28, 2010 at 10:40

1 Answer 1

Reset to default
4 
'/\w*(?=(?:\((.*)\))?)/'
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