Pointer to an array of pointers in Pascal

Question

I don't know how to access the content of an array of pointers by a pointer. Here's an example:

Type
    PInteger = ^Integer;
    IntegerArrayP = array of PInteger;
    PIntegerArrayP = ^IntegerArray;

var
    variable: Integer;
    parrp: PIntegerArrayP;
    arrp: IntegerArrayP;
begin
    SetLength(arrp, 5);
    parrp := @arrp;
    For variable := Low(arrp) to High(arrp) do
    begin
        arrp[variable] := New(PInteger);
        (parrp^)[variable]^ := variable;
        WriteLn('parrp: ', arrp[variable]^);
    end;
end.

In my opinion it should be done like this (ptabp^)[variable]^ := variable; But I guess I'm wrong.

MBo · Accepted Answer · 2014-12-06 15:52:48Z

1

You are right. Parens might be omitted.
What pascal compiler do you use? Proper usage of New routine:

 New(arrp[variable]) ;
 parrp^[variable]^ := variable;

P.S. Do you really need these pointer types here?

P.P.S. Now I see an error: PIntegerArrayP = ^IntegerArrayP;

edited Dec 6, 2014 at 15:52

answered Dec 6, 2014 at 15:41

MBo

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3 Comments

Tomasz Kasperczyk Over a year ago

I'm using free pascal. I've also tried to compile it on an online compiler. Check it out here: ideone.com/rSkhTQ

Tomasz Kasperczyk Over a year ago

Well I don't need all of these pointer types. I'm just practising.

MBo Over a year ago

You mixed common type and your own type by accident. See addition

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