Python - Regex did not match string

Question

I am trying to get last regex match on a message broadcast by socket, but it returns blank.

>>> msg = ':morgan.freenode.net 353 MechaBot = #xshellz :MechaBot ITechGeek zubuntu whitesn JarodRo SpeedFuse st3v0 anyx danielhyuuga1 AussieKid92 JeDa Failed Guest83885 RiXtEr xryz D-Boy warsoul buggiz rawwBNC MagixZ fedai Sunborn oatgarum dune SamUt Pythonista_ +xinfo madmattco BuGy azuan DarianC stupidpioneers AnTi_MTtr JeDaYoshi|Away PaoLo- StephenS chriscollins Rashk0 morbid1 Lord255 victorix [DS]Matej EvilSoul `|` united Scrawn avira ssnova munsterman Logxen niko gorut Jactive|OFF grauwulf b0lt saapete'
>>> r = re.compile(r"(?P<host>.*?) (?P<code>.*?) (?P<name>.*?) = (?P<msg>.*?)", re.IGNORECASE)
>>> r.search(msg).groups()
(':morgan.freenode.net', '353', 'MechaBot', '')

vks · Accepted Answer · 2014-12-07 14:15:31Z

1

(?P<host>.*?) (?P<code>.*?) (?P<name>.*?) = (?P<msg>.*)

Try this.This works.See demo.Your code use .*? whch says match as few characters as you can.So while it your previous you have used .*? <space> it matches upto first space it encounters,in the last you have no specified anythng.So it did not match anythin as it s in lazy mode.

https://regex101.com/r/aQ3zJ3/1

You can also use

(?P<host>.*?) (?P<code>.*?) (?P<name>.*?) = (?P<msg>.*?)$

which says match lazily upto end.

edited Dec 7, 2014 at 14:15

answered Dec 7, 2014 at 14:07

vks

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2 Comments

Daniel Hyuuga Over a year ago

Okay that works. Could you explain why ? isn't necessary please?

Aran-Fey Over a year ago

@DanielHyuuga: If you make the last group non-greedy, it'll match the empty string. Regex doesn't attempt to consume all of the input string, as you probably think. As soon as the pattern matches entirely, it's over.

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