extending a javascript function with parameters

Question

I think extending the function is working correctly but I am not sure how to handle the parameters that are passed into the function, right now I get a x is undefined error.

Original function:

_adloadCallback = function(x, y) {
  //
}

Extended function:

(function() {
 _adLoadCallbackExtend =_adloadCallback();
 _adloadCallback = function() {
    console.log("Before");
   _adLoadCallbackExtend.apply(this, arguments);
    console.log("After");
  }
})();

Remove the () in _adLoadCallbackExtend =_adloadCallback();. You want to set the variable to the function, not call it. Also, you should probably add var there. — gen_Eric
– gen_Eric, Commented Dec 8, 2014 at 22:18

Havvy · Accepted Answer · 2014-12-08 22:18:22Z

1

On line two, you are seting _adLoadCallbackExtend to being the result of calling _adloadCallback instead of setting it to _adloadcallback itself, which is what I think you are trying to do. Just get rid of the () at the end of the second line.

answered Dec 8, 2014 at 22:18

Havvy

1,51115 silver badges29 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

gen_Eric · Accepted Answer · 2014-12-08 22:22:37Z

1

_adLoadCallbackExtend =_adloadCallback();

should be

_adLoadCallbackExtend =_adloadCallback;

your way has _adLoadCallbackExtend be the result of calling _adloadCallback with no arguments instead of a "pointer" to the function

edited Dec 8, 2014 at 22:22

gen_Eric

228k42 gold badges304 silver badges343 bronze badges

answered Dec 8, 2014 at 22:19

Leroy Stav

7184 silver badges13 bronze badges

Collectives™ on Stack Overflow

extending a javascript function with parameters

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related