I have a String that I want to split;
String x = "abc4.5efg2hij89k.9";
I want the output as
abc, 4.5, efg, 2, hij, 89, k, .9
I can easily split across digits and non digits however '.' is considered a character.
x.split("(?<=\\D)(?=\\d)|(?<=\\d)(?=\\D)")
[abc, 4, ., 5, efg, 2, hij, 89, k., 9]
What is the best way of supporting doubles?
Have you considered letter characters instead of using the \D token?
String s = "abc4.5efg2hij89k.9";
String[] parts = s.split("(?<=[a-z])(?=[\\d.])|(?<=\\d)(?=[a-z])");
System.out.println(Arrays.toString(parts));
Output
[abc, 4.5, efg, 2, hij, 89, k, .9]
You could do matching instead of splitting and then store the matches to an array list.
[^\\d.]+|\\d*(?:\\.\\d+)?
String x = "abc4.5efg2hij89k.9";
Pattern regex = Pattern.compile("[^\\d.]+|\\d*(?:\\.\\d+)?");
Matcher matcher = regex.matcher(x);
ArrayList<String> returnValue= new ArrayList<String>();
while(matcher.find())
{
if(matcher.group().length() != 0)
{
returnValue.add(matcher.group());
}
}
System.out.println(returnValue);
Output:
[abc, 4.5, efg, 2, hij, 89, k, .9]
(?<=[a-zA-Z])(?=[^a-zA-Z])|(?<=[^a-zA-Z])(?=[a-zA-Z])
Split by this.See demo.
[A-Z,a-z]to exclude.from matching