JSONException: Value of type java.lang.String cannot be converted to JSONArray

Question

There are codes I am using:

try {
       resultObject = new JSONObject(URLDecoder.decode(result, "UTF-8"));// no problem here
       resultJsonArray = resultObject.getJSONArray("data"); // error comes when run this line.

    } catch (UnsupportedEncodingException e) {
                        e.printStackTrace();
                    }

This is the whole error information:

org.json.JSONException: Value [{"first_name":"aig","phone_no":"3659428","passcode":"aig","last_name":"aig","user_id":"03343785-2714-43a5-a566-f4d9877ccafa","email_id":"[email protected]"},{"first_name":"aig","phone_no":"635448448","passcode":"aig","last_name":"aig","user_id":"5dc26dcc-3f81-434a-b293-48438f2f920a","email_id":"[email protected]"}] at data of type java.lang.String cannot be converted to JSONArray

After being formatted(http://jsonformatter.curiousconcept.com/), the JSON string will be like this:

{  
   "response":"Success",
   "tablename":"USER_INFO",
   "transaction_type":"MODIFICATION_PULL_RESPONSE",
   "data":"[{\"first_name\":\"aig\",\"phone_no\":\"3659428\",\"passcode\":\"aig\",\"last_name\":\"aig\",\"user_id\":\"03343785-2714-43a5-a566-f4d9877ccafa\",\"email_id\":\"[email protected]\"},{\"first_name\":\"aig\",\"phone_no\":\"635448448\",\"passcode\":\"aig\",\"last_name\":\"aig\",\"user_id\":\"5dc26dcc-3f81-434a-b293-48438f2f920a\",\"email_id\":\"[email protected]\"}]"
}

There must not be any String or Space before starting of JSONArray or JSONObject i.e.root must be like this [ or '{'. — Nitin Misra
– Nitin Misra, Commented Dec 19, 2014 at 6:34
Possible duplicate of Value of type java.lang.String cannot be converted to JSONArray and JSONException: Value of type java.lang.String cannot be converted to JSONObject. — jww
– jww, Commented Dec 19, 2014 at 6:37
@jww I checked all those threads before I asked my question. Somehow my problem is still here after trying those solutions. — Sam003
– Sam003, Commented Dec 19, 2014 at 6:44
@Nitin Misra I checked my json string using jsonformatter.curiousconcept.com. It is valid json string. — Sam003
– Sam003, Commented Dec 19, 2014 at 6:44
Hey, friends. I tried my codes in Eclipse, and they works fine. But they don't work in Android Studio. Any idea will be appreciated. Thanks — Sam003
– Sam003, Commented Dec 19, 2014 at 6:52

Charan Ghate · Accepted Answer · 2014-12-19 06:46:00Z

0

Please avoid the ""(Double quote characters) directly cause JSON through an exception while parsing it, always use \ Before these characters,

A string is a sequence of zero or more Unicode characters, wrapped in double quotes, using backslash escapes. A character is represented as a single character string. A string is very much like a C or Java string. .It may help you.

answered Dec 19, 2014 at 6:46

Charan Ghate

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1 Comment

Sam003 Over a year ago

Thanks. Actually I tried my codes in Eclipse, it works. But when I trying to do that in Android Studio, it doesn't. It is wired.

Sagar Maiyad · Accepted Answer · 2014-12-19 07:26:45Z

0

you doing wrong. try like below code:

try {

   resultJsonArray = resultObject.getJSONArray(result);

} catch (UnsupportedEncodingException e) {
                    e.printStackTrace();
                }

edited Dec 19, 2014 at 7:26

answered Dec 19, 2014 at 6:35

Sagar Maiyad

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3 Comments

Sam003 Over a year ago

Hi, MunimJi, thanks. I tried your codes, Same error.

Sagar Maiyad Over a year ago

check my edited answer. i think it should be like this.

Sam003 Over a year ago

Hi, MunimJi, thanks. Please check the solution I just posted. It don't know why it works. Cheers.

Sam003 · Accepted Answer · 2014-12-19 07:27:37Z

0

After testing for a while, I solved it in a wired way:

**Before:**

       try {
          resultObject = new JSONObject(URLDecoder.decode(result, "UTF-8"));// no problem here
          resultJsonArray = resultObject.getJSONArray("data"); // error comes when run this line.

       } catch (UnsupportedEncodingException e) {
          e.printStackTrace();
       }


**After**

      try {
          resultObject = new JSONObject(URLDecoder.decode(result, "UTF-8"));// no problem here
          resultJsonArray = new JSONArray(resultObject.get("data").toString()); // Works!!!

       } catch (UnsupportedEncodingException e) {
          e.printStackTrace();
       }

It is really wired. I have no idea why this works.

answered Dec 19, 2014 at 7:27

Sam003

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2 Comments

vilpe89 Over a year ago

what the h.. is wired

Tino Over a year ago

I got the same issue! Your solution resultJsonArray = new JSONArray(resultObject.get("data").toString()); is working for me. Does someone know what is happening here? thank you anyway for this workaround, btw: i guess you mean "weird" not "wired"

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