Java/Android UnknownHostException

Question

I have the following code to pass an IP to some package that looks up the country.

WebServiceClient client = new WebServiceClient.Builder(42, "license_key").build();
InetAddress ipAddress = InetAddress.getByName("128.101.101.101");
CountryResponse response = client.country(ipAddress);

The problem is, that this gives me the error:

unreported exception UnknownHostException; must be caught or declared to be thrown

What am I doing wrong?

Well, the compiler tells you what you are doing wrong; you have to handle the exception. — fge
– fge, Commented Dec 20, 2014 at 21:59
Place it in the try catch block so the exception is handled properly — display name
– display name, Commented Dec 20, 2014 at 22:01

Gabe Sechan · Accepted Answer · 2014-12-20 22:01:31Z

1

One of those functions (at least) declares that exception as throwable. In Java, all declared throwable exceptions must be caught- you don't need to do anything in the exception handler (although logging it at least is a good idea), but it has to be there, or the function that calls it must also declare those exceptions as throwable (and its caller would then need to catch them). Its a mechanism in Java called "checked exceptions". A lot of people don't like them and many consider it to be a mistake, but those parts of the Java library that use it will probably never change, so you have to live by the rules.

answered Dec 20, 2014 at 22:01

Gabe Sechan

94.7k9 gold badges92 silver badges135 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Java/Android UnknownHostException

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related