Return Multiple Objects Using ASP.NET MVC'S JsonResult Class

Question

Is it possible to Multiple Objects Using ASP.NET MVC'S JsonResult Class.... Here is a controller method which returns json object of my records but i also want to pass the count value....

var materials = consRepository.FindAllMaterials().AsQueryable();
var count = materials.Count();
var results = new PagedList<MaterialsObj>(materials, currentPage-1, pageSize);
return Json(results);

How to return count along with the results from asp.net mvc controller....

retired · Accepted Answer · 2010-05-04 12:19:20Z

21

How about creating an anonymous type and JSON'ing that?

e.g.

var resultCount = results.Count;
var genericResult = new { Count = resultCount, Results = results };
return Json(genericResult);

You can then eval your json string in your script as before but just query the Count and Results properties on your eval result.

answered May 4, 2010 at 12:19

retired

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4 Comments

retired Over a year ago

My assumption was you were calling the eval function yourself. If you've done a jQuery call specifying a json result type, it will already have done that.

Nick Over a year ago

@Oscar that is true for this case, but in cases where the data you want to obtain isn't a simple property, you would need to pass an object like Neil has demonstrated.

Jogi Over a year ago

how to read Count and Results in the ajax success property?

Shaiju T Over a year ago

@RehanKhan , check this to read Count and Results in the ajax success. Hope helps.

Brian Mains · Accepted Answer · 2012-10-29 00:04:10Z

0

There is a way to send multiple objects which are dynamically identified to send. See this.

edited Oct 29, 2012 at 0:04

Brian Mains

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answered Feb 29, 2012 at 13:41

yashpal

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1 Comment

Bart Over a year ago

Please instead of just linking to a blog include at least a summary of the answer here. By doing that your answer does not become invalid should the blog ever go offline. It makes your answer nicely self-contained. You can still link to the blog for further details.

Rajdeep · Accepted Answer · 2017-02-01 07:22:25Z

0

In C# part:

Using new keywork

var genericResult = new { homeworkData = homework, attachmentData = homeworkAttachment };
var result = this.Json(genericResult, JsonRequestBehavior.AllowGet);
return result;

In jquery side :

function getHomewrokDetailResponse(dataSent, result) {
if (result && result.homeworkData) {
    homeworkId = result.homeworkData.homeworkId;

    ....
}
 if (result && result.attachmentData) {
    xy = result.attachmentData.xyz;

    ....
}

answered Feb 1, 2017 at 7:22

Rajdeep

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