img src not working with php and php variables

Question

foreach ($values as $value)
    {

        echo("<td> "."<img src= \"$value[\"img\"]\" />"."</td>"); 
        print("</tr>");
    }

I am basically trying to print the image whose path I've stored in mysql database. However I am getting very confused with the img src in html and after trying a lot of ways, the image is still not being printed out.

ElefantPhace · Accepted Answer · 2014-12-28 16:52:24Z

4

you're escaping too many times. just be simple about it:

echo '<td><img src="'.$value['img'].'"/></td>';

You could also do it this way:

echo "<td><img src='{$value['img']}' /></td>";

answered Dec 28, 2014 at 16:52

ElefantPhace

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Comments

cirtrus · Accepted Answer · 2014-12-28 16:53:00Z

-1

I've corrected your code.

foreach ($values as $value)
    {

        echo("<td> "."<img src='".$value["img"]."' />"."</td>"); 
        print("</tr>");
    }

answered Dec 28, 2014 at 16:53

cirtrus

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