I'm working on a Python project and I want to do something like the next example, but is incorrect. I need some help, please!
names = ['name1', 'name2']
for name in names:
class name:
[statements]
Thank you!
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Explain what you are trying to accomplish, and in what way this is "incorrect".Scott Hunter– Scott Hunter2014-12-29 23:05:10 +00:00Commented Dec 29, 2014 at 23:05
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Related: How can you dynamically create variables in Python via a while loop? and How do you create different variable names while in a loop? (Python)Ashwini Chaudhary– Ashwini Chaudhary2014-12-29 23:13:49 +00:00Commented Dec 29, 2014 at 23:13
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1 Answer
The class statement requires a hard-coded class name. You can use the type function, however, to create such dynamic classes.
names = ['name1', 'name2']
class_dict = {}
for name in names:
# statements to prepare d
class_dict[name] = type(name, (object,), d)
Here, d is a dictionary that should contain any attributes and methods that you would have defined in your class. class_dict is used to store your class objects, as injecting dynamic names directly into the global namespace is a bad idea.
Here is a concrete example of using the type function to create a class.
d = {}
d['foo'] = 5
def initializer(self, x):
self.x = x + 6
d['__init__'] = initializer
MyClass = type('MyClass', (object,), d)
This produces the same class as the following class statement.
class MyClass(object):
foo = 5
def __init__(self, x):
self.x = x + 6
2 Comments
Ashwini Chaudhary
As
type() creates an object of <type 'type'> (not classobj) we can replace (object,) with (). But yeah Explicit is better than implicit. :-)
chepner
Ah, true, I see a
type instance inherits from object whether or not you include object in the base-class tuple.