2 Dimensional Char Array C++

Question

Is there such a way to initialize a char array and then loop through them all and change the value? I'm trying to create a table like structure.

I just keep getting errors like "Cannot initialize a value of type 'char' with an lvalue of type 'const char [3]'.

I'm using Xcode 6.1.1 for development

int width = 25;
int height = 50;


char board [50][25] = {""}; // height x width

for (int i = 0; i < width; i++) {
    for (int j = 0; i < height; i++) {

        if (i == 0) {
            board[i][j] = {"||"};
        }

    }
}

Each element in your 2D array is a single char.

Joseph Mansfield
– Joseph Mansfield

2014-12-30 00:12:57 +00:00
Commented Dec 30, 2014 at 0:12 — Joseph Mansfield
– Joseph Mansfield, Commented Dec 30, 2014 at 0:12

M.M · Accepted Answer · 2014-12-30 00:14:15Z

3

The problem is with board[i][j] = {"||"}; . The string "||" cannot be implicitly converted to a single character.

It's not clear what you are trying to do; each cell of the board is a char, and || is two chars. Two doesn't go into one. Perhaps you meant:

board[i][j] = '|';

Also, your loop nesting is backwards (the height loop should be the outer one). The indexing of an array is the same as its declaration, so for board[i][j] to work when the declaration was char board[50][25], i must be ranging from 0 to 49 .

An improvement would be:

int const width = 25;
int const height = 50;
char board[height][width] = {};

for (int h = 0; h < height; h++)
    for (int w = 0; w < width; w++)

answered Dec 30, 2014 at 0:14

M.M

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Comments

Dtor · Accepted Answer · 2014-12-30 00:14:07Z

0

Set the characters in the array with single quotes, not double. So:

board[i][j] = '|';

Also, notice that you can only put a single character in each position

answered Dec 30, 2014 at 0:14

Dtor

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