How to replace a character in a string with a non ascii character in python?

Question

I want to replace the number sign (#) with a character similar to that called music sharp sign (♯). I tried the following line but didnt work.

res['n'].replace('#', '♯')

I also tried these and also didnt work fine.

res['n'].replace('#', u'♯')
res['n'].replace('#', '\xe2')

Anyone got any idea about the situation?

It "didnt work". What was the error? It works perfectly fine to me. What is res? — sushain97
– sushain97, Commented Dec 31, 2014 at 9:24
Maybe you were expecting replace() to modify the string in place? replace() doesn't do that; it creates a new string. You would need to write res['n'] = res['n'].replace('#', '♯'). — Warren Weckesser
– Warren Weckesser, Commented Dec 31, 2014 at 9:32
Good point @ceremcem: Also, '\xe2\x99\xaf'.decode('utf-8') == u'\u266f'. — PM 2Ring
– PM 2Ring, Commented Dec 31, 2014 at 12:06

Prakash Kuma · Accepted Answer · 2014-12-31 09:35:08Z

2

res="He##o"
res=res.replace("#","♯")
print res

o/t He♯♯o

answered Dec 31, 2014 at 9:35

Prakash Kuma

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Comments

nEO · Accepted Answer · 2014-12-31 09:27:16Z

0

import re
text = ' '
re.sub(' ', '\x00', text)

Why not you use this?

answered Dec 31, 2014 at 9:27

nEO

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Why do you think this is even vaguely relevant to the question?

RemcoGerlich · Accepted Answer · 2014-12-31 09:45:06Z

0

Replace returns the changed string, strings cannot be changed themselves. Try

res['n'] = res['n'].replace('#', '♯')

answered Dec 31, 2014 at 9:45

RemcoGerlich

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