Launch java app in specific version with bash script

Question

I wish to open certain java applications (For example, MapTools, part of RPtools) with Oracle Java 6 for compatibility purposes using shell scripts.

In the simplest possible terms, what do I need to do to make a working shell script for an application to launch with a specific java version on Ubuntu?

Note that for maximum usefulness, specific application names should not be used. Instead use tags such as "App" to determine where the name of the application or it's path should go.

See stackoverflow.com/questions/10757851/…

gknicker
– gknicker

2015-01-05 05:17:24 +00:00
Commented Jan 5, 2015 at 5:17 — gknicker
– gknicker, Commented Jan 5, 2015 at 5:17

Prakash Bhagat · Accepted Answer · 2015-01-05 06:28:32Z

2

Specify absolute path of java executable of the JRE version,

[JRE_HOME]/bin/java -jar jar_name.jar

e.g.

/usr/lib/jvm/oracle-7-jre/bin/java -jar exec.jar

answered Jan 5, 2015 at 6:28

Prakash Bhagat

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Community · Accepted Answer · 2017-05-23 11:50:56Z

0

Use the full path to the desired java.exe in your command line.

See Run a JAR file using a specific JRE.

edited May 23, 2017 at 11:50

CommunityBot

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answered Jan 5, 2015 at 5:18

gknicker

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