C++ multidimensional dynamic array

Question

Let's say I have this to create a multidimensional array dynamically:

int* *grid = new int*[gridSizeX];

for (int i=0; i<gridSizeX; i++) {
  grid[i] = new int[gridSizeY];
}

Shouldn't be possible now to access elements like grid[x][y] = 20?

Yes. {Assuming x is within [0, gridSizeX) and y is within [0, gridSizeY).} I recommend you use std::vector to manage memory for you. — GManNickG
– GManNickG, Commented May 6, 2010 at 1:31
lets see here, in the related links we find stackoverflow.com/questions/1024772/… and stackoverflow.com/questions/799373/… and stackoverflow.com/questions/1584100/… and there are others: I've answered at least three versions of this many moons ago. — dmckee --- ex-moderator kitten
– dmckee --- ex-moderator kitten, Commented May 6, 2010 at 1:45
AraK answered something similar extensively here: stackoverflow.com/questions/1946830/… — Georg Fritzsche
– Georg Fritzsche, Commented May 6, 2010 at 2:13

Georg Fritzsche · Accepted Answer · 2010-05-06 01:32:35Z

3

Yes, this should work fine.

But... you might want to consider using standard containers instead of manually managing memory:

typedef std::vector<int> IntVec;
typedef std::vector<IntVec> IntGrid;
IntGrid grid(gridSizeX, IntVec(gridSizeY));

grid[0][0] = 20;

answered May 6, 2010 at 1:32

Georg Fritzsche

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Comments

nevelis · Accepted Answer · 2010-05-06 01:33:09Z

0

Yes - but in C/C++ it will be laid out as grid[y][x].

answered May 6, 2010 at 1:33

nevelis

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1 Comment

nevelis Over a year ago

Pardon me - I mean it will be laid out in memory as grid[y][x]. And agree with gf - in C++ you may want to use standard containers, as then you can check their .size() and avoid any slipups :)

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