How to export every function of a bash script for use with gtkdialog?

Question

I have a bash script of the form:

cat  << EOF > stackoverflow_source.sh
#!/bin/bash
function f1 () {
         echo This is the first function.
}
function f2 () {
         echo This is the second function.
}
EOF

and its GUI with gtkdialog:

$ cat  << EOF > stackoverflow_gui.sh
#! /bin/bash
source stackoverflow_source.sh
export MAIN_DIALOG='
<window window_position="1" title="StackOverflow Question">
 <hbox>
  <button>
   <label>Function One</label>
   <action>f1</action>
  </button>
  <button>
   <label>Function Two</label>
   <action>f2</action>
  </button>
 </hbox>         
</window>'
gtkdialog  --program=MAIN_DIALOG
EOF

So after running:

$ source stackoverflow_source.sh

I get:

$ f1
This is the first function.

but when I click the corresponding button in the gui (even after sourcing the script) I get

sh: f1: command not found

When I export the functions with

$ export -f f1 && export -f f2

they do work in the gui (sh stackoverflow_gui and clicking their buttons, echos the text).

Is there a way to export every function in my stackoverflow_source.sh script? (In my real source script I have hundreds of functions and I do not want to do it one by one). Alternatively, is there a better way to do what I want?

pgl · Accepted Answer · 2015-01-09 12:42:34Z

2

This should work for you:

for func in $(declare -F | cut -f3 -d' ')
do
    export -f $func
done

Or, more concisely (but less readable):

export -f $(declare -F | cut -f3 -d' ')

answered Jan 9, 2015 at 12:42

pgl

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