import re
look = r'Template.11_31.Single-Volume'
pattern = r'11.31'
match = re.search(pattern,look)
print re.findall(pattern,look)
if (match is not None):
print match.group(0)
Answer:
['11_31']
11_31
I want it to match 11.31 or 1131 but here it also matches 11_31
Problem is in your regex 11.31 dot will match any character.
You can use this regex:
pattern = r'11\.?31'
This will match 11.31 or 1131 but not 11_31 or 11:31 since \. matches a literal dot and \.? makes dot an optional match.
Example:
>>> print re.findall(pattern, "Template.11.31.Single-Volume-1131-something")
['11.31', '1131']
pattern =r'11.31'
Here . can match anything so it will match _ in 11_31 as well. Either escape it (\.) or put it in character class ([.]) and add more to it as when required.
Use this
pattern =r'11[.]?31'
See demo.
