PHP foreach loop through multidimensional array

Question

I have an multidimensional array, how can I use it? I want to use each separate array in a for loop.

What I want to achive is to be able to put each part in my database like entry in db no. 0 -> 1 and 4 entry in db no. 1 -> 5 and 6 entry in db no. 2 -> 1 and 4 and 5 and 6

I have this code:

<?php 
    print_r($calculatie_id); 
    for ($i=0; $i<=3; $i++) 
{ 
?>  
<tr> 
    <td> 

    <?php 
    foreach ($calculatie_id[$i] as $value) 
    { 
        echo $value; 
    } 
?>

print_r($calculatie_id); gives 
Array ( [0] => Array ( [0] => 4 [1] => 6 ) [1] => Array ( [0] => 1 [1] => 5 ) [2] => Array ( [0] => 5 [1] => 6 ) [3] => )

But when using the foreach I only get 46

Some extra information:

This array is created by an multiple select in an for loop. Any other suggestions are welcome.

    for ($i=0; $i<=$aantal_regels_corr; $i++)
{ 
?> 
<tr>
    <td>

        <?php 
        // maak select name
        $calculatie_id = 'calculatie_id'.$i;

        // rest van formulier
        if($error_vergeten[$i] == "ja"){ $error_omschr = $error_omschr_vergeten[$i]; include('includes/input_error.php'); } ?>&nbsp;<textarea rows="7" cols="80" name="omschrijving[]" /><?php echo $omschrijving[$i]; ?></textarea>
    </td>
    <td colspan="2">
        <select multiple="multiple" width="50" size="7" name="<?php echo $calculatie_id ?>[]" style="width: 150px">
        <?php
            $sql_calc = "select id, naam, actief from sp_calculatie WHERE (offerte_id = '".$row['off_offerte']."' OR offerte_id = '".$offerte_id."') AND actief = 'ja' ORDER BY id ASC";
            $res_calc = mysql_query($sql_calc,$con);  
            while ($row_calc = mysql_fetch_assoc($res_calc)){
        ?>
            <option value="<?php echo $row_calc["id"] ?>"><?php if (empty($row_calc["naam"])) { echo $row_calc["id"]; } else { echo $row_calc["naam"]; } ?></option>
        <?php } ?></select>
    </td>
</tr>
<?php } ?>

Cristian · Accepted Answer · 2010-05-06 20:19:06Z

7

foreach($calculatie_id as $inner_arr)
    foreach($inner_arr as $value)
        echo $value;

Edit: you should try to learn and understand what's going on here. Then, you can do whatever you want with the code I wrote. You said: gives 14561456 I want to use $calculatie_id0=14 $calculatie_id1=56 $calculatie_id2=1456 etc Then, you will have to do something like this:

foreach($calculatie_id as $index => $inner_arr){
    echo "$calculatie_id$index = "
    foreach($inner_arr as $value)
        echo $value;
    echo "<br/>";
}

Or you can create those variables you want (which does not make any sense for me):

foreach($calculatie_id as $index => $inner_arr){
    ${"calculatie_id$index"} = '';
    foreach($inner_arr as $value)
        ${"calculatie_id$index"} .= $value;
    echo ${"calculatie_id$index"}."<br/>";
}

edited May 6, 2010 at 20:19

answered May 6, 2010 at 19:37

Cristian

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1 Comment

Muiter Over a year ago

Array ( [0] => Array ( [0] => 1 [1] => 4 ) [1] => Array ( [0] => 5 [1] => 6 ) [2] => Array ( [0] => 1 [1] => 4 [2] => 5 [3] => 6 ) [3] => ) gives 14561456 I want to use $calculatie_id0=14 $calculatie_id1=56 $calculatie_id2=1456 etc.

Daniel · Accepted Answer · 2010-05-06 19:54:29Z

3

Basically what you have is an array like this:

array(
 array(
  data
 )
)

All you need is:

foreach($yourArray as $innerArray)
 foreach($innerArray as $value)
  echo $value;

That will output what you want. I'm not particularly sure why you're doing a for() loop then a foreach.

answered May 6, 2010 at 19:54

Daniel

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Muiter Over a year ago

I have added more info to the opening post.

Mitch Dempsey · Accepted Answer · 2010-05-06 19:31:52Z

0

You need to nest your foreach loops (so you have a loop inside a loop)

answered May 6, 2010 at 19:31

Mitch Dempsey

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Comments

thesunneversets · Accepted Answer · 2010-05-06 19:49:24Z

0

You could try:

foreach ($calculatie_id as $key => $value) {
  echo "$calculatie_id:".$key;
  for ($i=0;$i<=count($value);$i++) {
    echo $value[$i];
  }
}

answered May 6, 2010 at 19:49

thesunneversets

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1 Comment

Muiter Over a year ago

thx but this is the result: Array:014Array:156Array:21456Array:3

Kip · Accepted Answer · 2010-05-06 20:40:25Z

0

I don't understand why your original code snippet isn't working. Could it be the fact that $calculatie_id[3] is not an array?

I tried this:

<?php

$calculatie_id = array ( array(4,6), array(1,5), array(5,6), '' );

for ($i=0; $i<=3; $i++) 
{ 
  if(!is_array($calculatie_id[$i]))
    continue;
  echo "$i: ";
  foreach ($calculatie_id[$i] as $value) 
  { 
    echo $value; 
  } 
  echo '<br/>';
}

And that prints:

0: 46
1: 15
2: 56

edited May 6, 2010 at 20:40

answered May 6, 2010 at 20:29

Kip

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2 Comments

Muiter Over a year ago

How to prevent tat is uses an array that doesn't exists?

Kip Over a year ago

@Muiter: well like i said, you can use if(!is_array($calculatie_id[$i])) continue; to go on to the next iteration of the loop

Muiter · Accepted Answer · 2010-05-07 14:35:00Z

0

Many thanks for helping me out this far but all the examples I try to implement are not working. I have been trying this script for over 2 weeks now. It seems I'm going all the wrong way.

I have put my code online at www.pws.nl/downloads/sp_offerte_add.rar. It must be easier then what I'm writing in the code right now.

answered May 7, 2010 at 14:35

Muiter

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