I am using an ArrayList of to create lists. For example:
Index 0: 1 3
Index 1: 4 5
Index 2: 1 3 7
How can I access the second element of the first index of the ArrayList? Couldn't find the answer on Google, so I asked here.
3 Answers
yourList.get(0)[1]; // that's it !!
If you want to iterate over it :
for (Integer[] outer : yourList) {
for(Integer inner : outer) {
System.out.println(inner);
}
}
1 Comment
Marian Pavel
If it was so simple why I couldn't find it over the internet, thanks a lot.Gonna try it ! Mark answer after time pass.
By your question, I am guessing you have something like this?
List<Integer[]> list = new ArrayList<Integer[]>();
Integer[] a1 = {1,3};
Integer[] a2 = {4,5};
Integer[] a3 = {1,3,7};
list.add(a1);
list.add(a2);
list.add(a3);
Then all you need to do is simply call:
Integer result = list.get(0)[1];
The get(0) pulls the first Integer[] out of the list, then to get the second element, you use [1]
Comments
where do you see the exception? have you tried this?
List<Integer[]> list = new ArrayList<Integer[]>(3);
Integer[] a1 = {1,3};
Integer[] a2 = {4,5};
Integer[] a3 = {1,3,7};
list.add(a1);
list.add(a2);
list.add(a3);
Integer result = list.get(0)[1];
There aren't any exception. The arraylist have three elementes because you have three elemente (a1,a2,a3),
ArrayListisn't an array ofInteger(s).