Using Ajax and passing JS variable to php variable, $_POST not recognizing data value

Question

I am using AJAX to pass a javascript variable to PHP. Everything was working well and dandy, and then I changed the security of how my php functions will execute. Here is my javscript code:

function writetofile(file, wellname, api){
   $.ajax({
    type: 'post',
    url: 'process.php',
    data: { 
        api: api,
        wellname: wellname,
        fileName: file,
        writetoFile: true
    },
    success: function(data){
        output(api + " : " + wellname + " has been added to: " + file);
    }
});

}

PHP:

// process.php
if ($_POST['writetoFile'])){ // i need to check here if writetofile is true, which it is
    $api = $_POST['api'];
    $wellname = $_POST['wellname'];
    $fileName = $_POST['fileName'];
    $break = "\n";
    $str = $api. " : ". $wellname . $break;
    $file = fopen($fileName,"a");
    fwrite($file, $str);
    fclose($file);
}

when I execute the javascript code, it doesn't write to the file, and yes, I have checked to see if the ajax request was accepted. It is, but i tried doing:

PHP

if ($_POST['writetoFile'] === true)){}

but that doesn't seem to be working either. Thank you for your help.

What happens when you var_dump($_POST)? You're also not doing any error checking. Add error reporting to the top of your file(s) right after your opening <?php tag error_reporting(E_ALL); ini_set('display_errors', 1); — Jay Blanchard
– Jay Blanchard, Commented Jan 8, 2015 at 16:32
Wow i feel really stupid, I am so sorry for asking this. I have been staring at this damn piece of code for the last hour only to find that I had an extra ) in my code... Please don't downvote this. Thank you. The error set up did hel me a lot though. — macas
– macas, Commented Jan 8, 2015 at 16:35
Is this your entire code or is it just a part of it? If this is really the code you are using, what bothers me is this: if ($_POST['writetoFile'])){ -> check the number of ). You have two. — N.B.
– N.B., Commented Jan 8, 2015 at 16:36

Jay Blanchard · Accepted Answer · 2015-01-08 16:39:51Z

1

Add error reporting to the top of your file(s) right after your opening <?php tag

error_reporting(E_ALL); 
ini_set('display_errors', 1);

You'll find that you have an extra closing parentheses in your if statement -

if ($_POST['writetoFile'] === true))
                             ------^

answered Jan 8, 2015 at 16:39

Jay Blanchard

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