Assign variable with variable in function

Question

Let's say we have

def Foo(Bar=0,Song=0):  
    print(Bar)
    print(Song)

And I want to assign any one of the two parameters in the function with the variable sing and SongVal:

Sing = Song
SongVal = 2

So that it can be run like: Foo(Sing=SongVal) Where Sing would assign the Song parameter to the SongVal which is 2. The result should be printed like so:

0
2

So should I rewrite my function or is it possible to do it the way I want to? (With the code above you get an error saying Foo has no parameter Sing. Which I understand why, any way to overcome this without rewriting the function too much? Thanks in advance!

Thomas Wouters · Accepted Answer · 2010-05-06 22:39:18Z

4

What you're looking for is the **kwargs way of passing arbitrary keyword arguments:

kwargs = {Sing: SongVal}
foo(**kwargs)

See section 4.7 of the tutorial at www.python.org for more examples.

answered May 6, 2010 at 22:39

Thomas Wouters

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1 Comment

user202459 Over a year ago

Worked, thanks! Only things that needed changing was Sing should equal a string Sing = "Song"

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