Split url into tab in javascript

Question

input:

"/desh/HRTY/THR/TDR/2015-01-09?passengers=STANDARD:1&returnDate=2015-01-10&max=0&withThac=false"

javascript:

var params = {};
var paramDelim = link.indexOf('?');
var parmeters = link.substring(paramDelim + 1, link.length);
var parts = parmeters.split('[&=]');

output of my js code:

0: "passengers=STANDARD:1&returnDate=2015-01-10&max=0&withThac=false"
length: 1

i want to split my url into a map with key:value like this

output:

origin:THR
destination:TDR
goDate:2015-01-09
passengers:STANDARD:1
returnDate:2015-01-10
max:0
withThac:false

My code not do exactly what i want in output, what is wrong ?

the is no '[&=]' found on the split so this is the expected behavior — Hacketo
– Hacketo, Commented Jan 9, 2015 at 10:15
You are using a string that contains 4 characters [&=] as a delimiter to split. Since the input does not contain [&=] you're getting only one big string as your result. Try putting it in a regular expression like ...split(/[&=]/). This stackoverflow.com/a/3560051/1389366 is a very nice explanation to your problem. — icke
– icke, Commented Jan 9, 2015 at 10:15

Hacketo · Accepted Answer · 2015-01-09 10:18:42Z

2

You should split with

var params = parmeters.split('&')

and then split all the values you get

for (var i = 0,len = params.length; i<len;i++){
    var data = params[i].split("=", 2);  // Max 2 elements

    var key = data[0];
    var value = data[1];
    ...
}

answered Jan 9, 2015 at 10:18

Hacketo

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Comments

Haydar C. · Accepted Answer · 2015-01-09 10:22:12Z

1

i think your wrong ' characters

var params = {};
var paramDelim = link.indexOf('?');
var parmeters = link.substring(paramDelim + 1, link.length);
/*--> i think used regexp. Clear ' Char. --> */var parts = parmeters.split(/[&=]/);

use this like..

good luck

answered Jan 9, 2015 at 10:22

Haydar C.

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Xotic750 · Accepted Answer · 2015-01-09 11:21:28Z

1

A possible solution using ECMA5 methods and assuming that your string is always the same pattern.

var src = '/desh/HRTY/THR/TDR/2015-01-09?passengers=STANDARD:1&returnDate=2015-01-10&max=0&withThac=false',
    slice = src.split(/[\/|?|&]/).slice(3),
    data = slice.reduce(function (output, item) {
        var split = item.split('=');

        output[split.shift()] = split.shift();

        return output;
    }, {
        origin: slice.shift(),
        destination: slice.shift(),
        goDate: slice.shift()
    });

document.body.appendChild(document.createTextNode(JSON.stringify(data)));

answered Jan 9, 2015 at 11:21

Xotic750

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