For loop printing characters on same line in Javascript

Question

I have this code here, when I debug it, it prints out the characters on multiple lines but I want them to be on the same line in order to recompose the word inputted. For example, when I debug it inputting the word hello it prints out:

h
i
l
l
i

how ever I would like to print this: hilli. Any idea?? Thanks.

var say = prompt("name");

for ( var count = 0; count <= say.length; count++){

var letter = say.charAt(count);

  if (letter == "a" || letter == "e" || letter == "o" || letter == "u"){

  letter = "i";
  }

  console.log(letter);

}

Concat the values into a variable and use console.log() just once. — emerson.marini
– emerson.marini, Commented Jan 9, 2015 at 16:09
Even better. Use RegExp or regular string replacement to work out the occurrences and print the result. You don't need any loop here. — emerson.marini
– emerson.marini, Commented Jan 9, 2015 at 16:10

Alnitak · Accepted Answer · 2015-01-09 16:10:00Z

3

console.log always outputs each invocation on a line of its own.

If you want a single line, you'll have to coalesce the characters into a new string, and then output that after the loop.

For your particular code, you could also just use a regexp to do the whole thing.

name = name.replace(/[aeou]/gi, 'i');   // 'g' for global, 'i' for case-insensitive

or for case-sensitive:

name = name.replace(/[aeou]/g, 'i').replace(/[AEOU]/g, 'I');

There might be better ways of writing that last version, but the above is quick and self-explanatory.

answered Jan 9, 2015 at 16:10

Alnitak

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2 Comments

Daniel O Mensah Over a year ago

Thank you very much! I finally made it. However, could you please explain this ----name.replace(/[aeou]/g, 'i')---- to me.

Alnitak Over a year ago

It just means "replace every character (/g) in the set [aeou] with the letter i.

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