I have
s = "[[[ab_1]]] bla1 [[[cd_3]]] bla2 "
I want to split s into "bla1" and "bla2". the thing is, ab_1 and cd_3 are dynamic literals. they can be anything in form "letters_numbers".
I am stuck like never before.. I tried with split() but it is getting ugly because s can be a long string with multiple delimeters in it..
any pythonic ideas?
I think you want to use re.split.
Something like the following regular expression might do it:
In [11]: re.split("\s*\[{3}.*?\]{3}\s*", s)
Out[11]: ['', 'bla1', 'bla2 ']
In [12]: re.split("\s*\[{3}.*?\]{3}\s*", s.strip())[1:]
Out[12]: ['bla1', 'bla2']
s = "[[[ab_1]]] bla1 [[[cd_3]]] bla2 "
import re
print(re.findall("(?<=\s)\w+",s))
['bla1', 'bla2']
Or if you want to include punctuation:
s = "[[[ab_1]]] bla1 [[[cd_3]]] bla2!"
import re
print(re.findall(r"\s(\w+\S)",s)
['bla1', 'bla2!']
You can split the string and use str.isalnum() in a list comprehension :
>>> [i for i in s.split() if i.isalnum()]
['bla1', 'bla2']
import re
s = "[[[ab_1]]] bla1 [[[cd_3]]] bla2 "
print filter(bool, re.split('\W', s))
OUTPUT:
['ab_1', 'bla1', 'cd_3', 'bla2']
And if you want only the "bla"s:
s = "[[[ab_1]] bla1 [[[cd_3]]] bla2 "
print filter(lambda x: re.match('\w+|\s+', x), re.sub('\[.*?\]', ' ', s))
will output:
bla1 bla2
not not x? What is that about?
lambda x:x and it'll work just finefilter(bool, re.split('\W', s)) then. I just wondered why someone would think not not x was necessary.
s?