PHP - Count XML Child Nodes

Question

I have XML that looks like the following:

<?xml version="1.0" encoding="UTF-8"?>
<apiresponse>
  <response>
    <services>
      <service>
        <Carrier>Carrier1</Carrier>
      </service>
      <service>
        <Carrier>Carrier2</Carrier>
      </service>
      <service>
        <Carrier>Carrier3</Carrier>
      </service>
      <service>
        <Carrier>Carrier4</Carrier>
      </service>
    </services>
  </response>
</apiresponse>

This is stored inside the variable $result.

I want to count the number of nodes within services. How do I go about this when the services node doesn't have a name or ID?

I tried the following but it didn't work:

$xml = new SimpleXMLElement($result);
echo count($xml->services);

Thanks!

there is no <services> at the top of your xml. it'd be $xml->response->services — Marc B
– Marc B, Commented Jan 12, 2015 at 14:49

goldlife · Accepted Answer · 2015-01-12 14:52:49Z

1

you can simply use this:

echo $xml->response->services->service->count();

or you use a loop:

$xml = new SimpleXMLElement($result);

foreach ($xml as $services) {
    foreach($services as $service) {
        echo "<pre>";
        print_r($service->count());
        echo "</pre>";
    }
}

edited Jan 12, 2015 at 14:52

answered Jan 12, 2015 at 14:47

goldlife

1,9994 gold badges29 silver badges56 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Lee Over a year ago

This works great! If I wanted to loop through each service and grab the Carrier value, how would I edit your loop? I can't quite get my head round it - Thanks!

goldlife Over a year ago

another foreach to loop the services:

foreach ($xml as $services) {     foreach($services as $service) {         foreach($service as $carrier) {             echo $carrier->Carrier . '<br/>';         }     } }

Collectives™ on Stack Overflow

PHP - Count XML Child Nodes

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related