Checkbox checked with PHP form post?

Question

How do I check a checkbox?

I've tried 1, On, and Yes. That doesn't work. Putting the worked "checked" alone works, but then how do I check with PHP after a form post of the checkbox is checked?

<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />

Peter Mortensen · Accepted Answer · 2019-07-08 01:28:37Z

4

A checkbox will only be a successful control if it is checked.

Controls that are not successful are not submitted as data.

Therefore, you can tell if a checkbox is checked by seeing if its value has been submitted.

E.g.

if ($_POST['chk']['newmsg2'] == 1) {

edited Jul 8, 2019 at 1:28

Peter Mortensen

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answered May 8, 2010 at 0:34

Quentin

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Michal M · Accepted Answer · 2010-05-08 00:16:47Z

0

<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" <?php if ($_POST['chk']['newmsg2']): ?>checked="checked"<?php endif; ?> />

answered May 8, 2010 at 0:16

Michal M

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Comments

Peter Mortensen · Accepted Answer · 2019-07-08 01:29:14Z

0

Here is the code;

<form action="test.php" method="POST">
    <input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
    <input type="submit">
</form>

<?php
    $check = $_POST['chk']['newmsg2'];
    echo "***$check****"
?>

If it is checked $check will show 1.

edited Jul 8, 2019 at 1:29

Peter Mortensen

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answered May 8, 2010 at 0:16

Adnan

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1 Comment

Patrick Over a year ago

nothing is being updated? like you said in your example it should return 1 when checked. I checked the box and submited the form and nothing was saved to the database. the mysql update is correct, I tested it with a forced manual insert and its correct. this is my form: <input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] /> and then i did a simiple test php mysql submit if(!isset($_POST['edit_prefs'])) { $mewmsg = $_POST['chk'][newmsg1]; mysql_query("UPDATE social_members_prefs SET m_newmsg='".$newmsg."' WHERE p_id='".$m_id."'"); }

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