Fetch just http URL from the string in PHP

Question

I have been trying to fetch just the URL from the following string but unsuccessful. How can I do that, any tips?

$string='<b><u>Neale v Commonwealth
Bank of Australia</u></b><b>
[2014] NSWCA 443</b><br>

Court of Appeal of New South Wales<br>

Leeming JA<br>

Appeal - competency - bank was successful judgment creditor in proceedings brought by applicant and his company - bank sought that appeal be dismissed as incompetent or for want of prosecution - requirement that, if well-funded, sophisticated, regular litigant is to object to competency of appeal brought by litigant in person, objection should be made promptly - ability to fund appeal - held: bank had not explained why it did not
make prompt objection - extension of time to seek dismissal of proceedings as incompetent refused - appeal not self-evidently hopeless - severe prejudice ifapplicant denied right of appeal on merits of very substantial judgment - there
had been some explanation for delay and non-compliance with Court procedure -
no particular prejudice to bank - guillotine order made.<br>

<a rel="nofollow" target="_blank" href="http://www.caselaw.nsw.gov.au/action/PJUDG?jgmtid=176362">Neale</a> (B)<br>';

$url=preg_match('/(http:\/\/)(.*)/', $string, $link);
echo $link[0];

OUTPUT: http://www.caselaw.nsw.gov.au/action/PJUDG?jgmtid=176362">Neale (B)

The script is adding extra characters after the URL which shouldn't be there.

try to just capture the href value. and better yet just use an HTML parser (DOMDocument) — Kevin
– Kevin, Commented Jan 15, 2015 at 5:59

Yash · Accepted Answer · 2015-01-15 06:05:38Z

2

Try

$url = preg_match('/(http:\/\/)(.*)"/is',$string,$matches);
 echo $matches[2]; // Your answer

you missed ' " ' in your regular expression.

answered Jan 15, 2015 at 6:05

Yash

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Gurpreet · Accepted Answer · 2015-01-15 06:21:56Z

2

As you are extracting it from a HTML Code and your url is in href attribute, you may use

$url=preg_match('/href="([^"]*)"/', $string, $link);
echo $link[1];

edited Jan 15, 2015 at 6:21

answered Jan 15, 2015 at 6:10

Gurpreet

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Noman Ur Rehman · Accepted Answer · 2015-01-15 06:06:15Z

0

Here is the correct regular expression:

/(http://.+)"/

You might want to inspect the returned array to check the exact index of the value you want.

answered Jan 15, 2015 at 6:06

Noman Ur Rehman

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Adi Utama · Accepted Answer · 2015-01-15 06:08:19Z

0

Try to change the you regular expression to this one.

/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i

It should become like this.

$url = preg_match('/\b(?:(?:https?|ftp):\/\/|www\.)[-a-z0-9+&@#\/%?=~_|!:,.;]*[-a-z0-9+&@#\/%=~_|]/i', $string, $link);

I hope it'll help. Cheers.

Source

answered Jan 15, 2015 at 6:08

Adi Utama

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