Behavior or Java array

Question

I was writing a random piece of code and it is bothering me as to why the output is 100000000 in this case:

public class HelloWorld {
    public static void main(String[] args) {
try {
    int[] array = {1};
    System.out.print(array[100000000]);
} catch (Exception e) {
    System.out.print(e.getMessage());
}
    }

}

Why does it print 100000000 and where can I read more about this behavior? Thank you.

Sotirios Delimanolis · Accepted Answer · 2015-01-19 18:51:20Z

4

You're trying to access an array element at an index that is greater than (or equal to) the length of the array. This will throw an ArrayIndexOutOfBoundsException exception.

ArrayIndexOutOfBoundsException#getMessage() seemingly returns a String representing the index you tried to access.

edited Jan 19, 2015 at 18:51

answered Jan 19, 2015 at 18:45

Sotirios Delimanolis

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1 Comment

vinay chilakamarri Over a year ago

I was expecting it to throw ArrayIndexOutOfBoundsException but I ignored the fact that I was just printing the message in the exception. Thank you this was helpful!

Suketu Bhuta · Accepted Answer · 2015-01-19 18:58:25Z

2

Because that is what the message property of the exception java.lang.ArrayIndexOutOfBoundsException thrown is set to. Try adding e.printStackTrace(); in the your catch block and it will print something like :

java.lang.ArrayIndexOutOfBoundsException: 100000000 at com.xxx.SomeTest.main(SomeTest.java:<< line number >>)

answered Jan 19, 2015 at 18:58

Suketu Bhuta

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