JQuery Function Call in another function

Question

$.save1= function(){
    var value = $("form#form1").serialize();
    send(value);
}

$.save2= function(){
    var value = $("form#form2").serialize();
    send(value);
}

$.save3= function(){
    var value= $("form#form3").serialize();
    send(value);
}

$.send= function(value){
    value = value + "&do=titlechange";
    $.ajax({
        url: "php_script.php",
        data: value,
        dataType: "json",
        type:"post",
        success: function(res){
            alert(res);     
        }
    });
}

I have 3 different form in same page. Also i have 3 different button, but i want to send values to same .php file. My code is above, but i could not call send function, in "save" functions. Save functions are binded buttons onclick.

OK, so what's the question?

Roamer-1888
– Roamer-1888

2015-01-24 11:30:29 +00:00
Commented Jan 24, 2015 at 11:30 — Roamer-1888
– Roamer-1888, Commented Jan 24, 2015 at 11:30

Bhojendra Rauniyar · Accepted Answer · 2015-01-24 11:29:07Z

2

Replace send(value); with $.send(value); as you're creating function with variable name $.send.

$.save1= function(){
    var value = $("form#form1").serialize();
    $.send(value);
}

$.save2= function(){
    var value = $("form#form2").serialize();
    $.send(value);
}

$.save3= function(){
    var value= $("form#form3").serialize();
    $.send(value);
}

$.send= function(value){
    value = value + "&do=titlechange";
    $.ajax({
        url: "php_script.php",
        data: value,
        dataType: "json",
        type:"post",
        success: function(res){
            alert(res);     
        }
    });
}

answered Jan 24, 2015 at 11:29

Bhojendra Rauniyar

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1 Comment

Dauezevy Over a year ago

thank you buddy, it works :) i will accept in 11 min

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