How to extract hostname and port from URL string?

Question

I need to extract hostname and port (if any) from an URL and here below is my code:

val regEx = """^(?:https?:\/\/)?(?:www\.)?(.*?)\//""".r
val url = regEx.split("http://www.domain.com:8080/one/two")
val hostname = url(url.length - 1).split("/")(0).split(":")(0)
val hasPort = url(url.length - 1).split("/")(0).split(":").length > 1
val port = if (hasPort) url(url.length - 1).split("/")(0).split(":")(1) else 80

The code above works as expected... but for sure in Scala there is a better way to get the same result.

How do I get hostname and port (if any) without using all those ugly splits?

Yes... that was the idea... but in this case I think what suggests Gabriele is the best solution. Tx. — j3d
– j3d, Commented Jan 25, 2015 at 15:08

Gabriele Petronella · Accepted Answer · 2015-01-24 19:24:07Z

19

Without reinventing the wheel, you can simply leverage java.net.URL

val url = new java.net.URL("http://www.domain.com:8080/one/two")
val hostname = url.getHost // www.domain.com
val port = url.getPort     // 8080

A minor difference, getPort returns -1 if no port is specified, so you have to handle that case explicitly.

val port = if (url.getPort == -1) url.getDefaultPort else url.getPort

answered Jan 24, 2015 at 19:24

Gabriele Petronella

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1 Comment

David Over a year ago

Note you should use new java.net.URI if you have urls like ws://domain.com:1234 (websockets). java.net.URL will throw on the ws protocol but java.net.URI is fine with it. java.net.URI has getHost and getPort too.

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