PHP calling index of an array with define constant

Question

I'm new to PHP and I have some problem with referencing a define constant to access array:

    define('NAME_INDEX', 0);
    ...
    if( $file ) {
        while( ($line = fgets($file))!==false ) {
            $array = explode(" , ", $line);
            echo "<br>$array[NAME_INDEX]<br>";
        }
    }

The error that I received:

Notice: Undefined index: NAME_INDEX

It prints out the value that I want when I do echo $array[0] though. Might anyone know what went wrong?

Works fine for me! Please show us your entire/full/real code and the exact error message — Rizier123
– Rizier123, Commented Jan 24, 2015 at 22:08
You don't have quotes around it do you? $array['NAME_INDEX'] won't work. — AbraCadaver
– AbraCadaver, Commented Jan 24, 2015 at 22:12
Thanks for your comment. I've updated my full code. Instead of showing the value that I want which is the name, it returns me the Notice message as stated in my question. I'm not sure what went wrong. — JDL Wahaha
– JDL Wahaha, Commented Jan 24, 2015 at 22:15
"<br>".$array[NAME_INDEX]."<br>" or "<br>{$array[NAME_INDEX]}<br>"; — Eugen
– Eugen, Commented Jan 24, 2015 at 22:16

Rizier123 · Accepted Answer · 2015-01-24 22:14:48Z

4

Just change this line:

echo "<br>$array[NAME_INDEX]<br>";

to:

echo "<br>" . $array[NAME_INDEX] . "<br>"; //OR echo "<br>{$array[NAME_INDEX]}<br>";

You can read more about concatenation in the manual: http://php.net/manual/en/language.operators.string.php

answered Jan 24, 2015 at 22:14

Rizier123

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1 Comment

JDL Wahaha Over a year ago

Thank you so much! I thought it would work because $array[0] works. 'Will accept the answer in 3 min.

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