Embeddin PHP into Javascript ,Uncaught SyntaxError: Unexpected identifier

Question

I am getting error Uncaught SyntaxError: Unexpected identifier
on line : TableX[i] = <?php echo $TableX[$x];  ?> ;
In the code below :
 index.php

for( i = 1 ; i<= <?php echo $num;?> ; i++) 
        {
            <?php for($x = 1 ; $x<=$num ; $x++ ) { ?>
            TableX[i] = <?php echo $TableX[$x];  ?> ;
            TableY[i] = <?php echo $TableY[$x];  ?> ;
        }
        <?php } ?>

I've wasted enough time on this , help would be really appreciated .

Are you getting that syntax error from PHP (at the server) or JS (on the browser console)? If the latter, is PHP enabled at all? — Bergi
– Bergi, Commented Jan 25, 2015 at 22:03

Mārtiņš Briedis · Accepted Answer · 2015-01-25 21:56:24Z

1

You can just output a php array as JSON:

<script>
var TableX = <?php echo json_encode($TableX);?>

answered Jan 25, 2015 at 21:56

Mārtiņš Briedis

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Neha Over a year ago

var TableX = <?php echo json_encode($TableX);?> ; var TableY=<?php echo json_encode($TableY);?> ; for(i = 1 ; i <= <?php echo $num ;?>; i++) {divToAdd = $("<div></div>"); $(divToAdd).addClass('dragged1'); $(divToAdd).offset({ left:TableX[i] , top:TableY[i]}) ; $('#frame').append(divToAdd); } It looks like there is syntax error in offset() , since when I run it , it does not take values rather it treats it as a text . guide me with this ...

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