passing an parameter to an array of objects

Question

I created an array of objects like this:

Handler handlers[] = new Handler[4];

Each handler object takes in a socket object as parameter. How do I pass through the socket for the handlers? I guess more generally how do I pass through arguments in an array of objects?

I've tried this:

handlers[1](someSocket);

and it (obviously?) didn't work.

You've created an array. You haven't created any Handler objects. — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Jan 26, 2015 at 0:57
@SotiriosDelimanolis okay, wow I think I've figured it out. Would I do this for all of the members of the array: handlers[0] = new Handler(listener.accept()); — iamtesla
– iamtesla, Commented Jan 26, 2015 at 1:00

Elliott Frisch · Accepted Answer · 2015-01-26 01:00:36Z

3

This

Handler handlers[] = new Handler[4];

Allocates room for 4 Handler instances, it doesn't allocate any actual Handler(s). You could do something like,

Handler[] handlers = new Handler[4];
for (int i = 0; i < handlers.length; i++) {
  handlers[i] = new Handler();
}

or even

Handler[] handlers = new Handler[] {
  new Handler(), new Handler(), new Handler(), new Handler()
};

answered Jan 26, 2015 at 1:00

Elliott Frisch

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chessprogrammer · Accepted Answer · 2015-01-26 01:02:28Z

1

Iterate over each element in the array. Create a new handler, pass it a socket, and store it in the array like this:

Handler handlers[] = new Handler[4];
for(int index=0;index<4;index++){
    handlers[index]= new Handler(socket);
}

answered Jan 26, 2015 at 1:02

chessprogrammer

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