In C++,
#include <iostream>
using namespace std;
int main ()
{
int i;
cin >> i;
cout << i;
return 0;
}
If we input a string to i, for example, "integer", it will display 0 when cout, which means that the string becomes 0. Could it be possible to make the string become some other integer, 10000 for example?
Sure - you can just do something like this:
#include <iostream>
using namespace std;
int main ()
{
int i = 10000; // initialise i to default value
int temp; // temporary integer for input validation
if (cin >> temp) // if valid integer entered
i = temp; // set i to entered integer (otherwise leave it at default value)
cout << i << endl;
return 0;
}
Compile and test:
$ g++ -Wall input.cpp
$ ./a.out
1234
1234
$ ./a.out
fred
10000
$
You'd have to input it to a string variable then examine the string and work out what to do
Foo, and a global operator function for>>for your class and a stream. You could even build syntax to supportcin >> setFooDefault(1) >>. Your class could even have a cast operator toint. That said, @PaulR's answer is more sensible.