Check this out
alert("wtf/http://google.com".split('/', 2));the resulted array contains 2 elements: wtf, http:.
Shouldn't it have wtf and the rest of the string? :/
3 Answers
The 2nd value passed to the split function limits your results but not where the array is split. To clarify the split separates it into 4 sections first then only returns the first two.
If you're trying to split out the wtf and the url try the following:
alert("wtf/http://google.com".split(/\/(.+)/,2))
1 Comment
Mouser
This code shows what the OP actually wanted and expected from split, it answers the question indirectly by saying that you need more logic to make this work. However it doesn't fully answer why the OP's approach is flawed.
The last integer in the function call specifies that split will return only two pieces. You just need to increase that number to 4, or remove it entirely.
alert("wtf/http://google.com".split('/'));
Comments
It's because you're splitting on the '/' and there are 4 slashes. It's just splitting up to the next '/' it finds, which would be '//google.com'.
If you do:
alert("wtf/http://google.com".split('/', 4));
you'll get all the pieces, just not separated into 2 chunks the way you want
.split(/\/\/)instead. Unless marked as global (/g), a regex will only match once.