PHP check if the first occurrence of an array exists in another array

Question

I have two arrays

$setWords = array ('one','two','three');
$setSentences = array('There is one cloud in the sky', 'A dog has four legs' , 'There are three cars parked outside');

I tried the following but it didn't work.

if(array_intersect($setWords , $setSentences) == true) {
print_r($setSentences);
}

In this case it would be There is one cloud in the sky and There are three cars parked outside.

AbraCadaver · Accepted Answer · 2015-01-30 22:27:56Z

3

I love preg_grep:

$result = preg_grep('/'.implode('|', $setWords).'/', $setSentences);
print_r($result);

edited Jan 30, 2015 at 22:27

answered Jan 30, 2015 at 21:14

AbraCadaver

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Comments

Erik · Accepted Answer · 2015-01-30 21:12:07Z

2

This won't work. The array_intersect function only checks values that are exactly the same. You need to manually run over the arrays and compare contents using the strpos function.

Something like this:

foreach( $setWords as $word ) {
  foreach( $setSentences as $sentence ) {
    if( strpos( $sentence, $word ) !== false ) {
      echo "found " . $word . " in " . $sentence . "<br />";
    }
  }
}

answered Jan 30, 2015 at 21:12

Erik

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1 Comment

user3758251 Over a year ago

Excellent. I can't believe it was so simple :-)

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