I am using jQuery's load() function when getting a page to a div like that:
content.php page is :
<script type="text/javascript">
$(".content").load("asd.php");
</script>
and asd.php is:
<script type="text/javascript">
alert("Hello World");
</script>
When load ajax finished alert() message appears 3 times. Actually it must appears only 1 time. So load() function get page 3 times.
How can I get the page a time?
You are probably facing the same problem as in this question.
Loading content which includes <script> elements into the page is massively unreliable. jQuery tries to paper over the issues but it doesn't quite succeed.
Best: Don't do it. Keep all your static JavaScript code separate from content loaded with load(), and use the post-loading callback to run any JavaScript code you need to bind to the new page content.
<script> to an element's innerHTML (as jQuery's html() or load() would). Keep scripts out of the content you are using AJAX to inject into the page.<script> in that content. It doesn't really make sense to, anyway: scripts are supposed to be run once per main page load, not on each sub-navigation. If the scripts include any logic that depends on not defining the same variable or function twice, or needs to run at document load time (ie. document.write()), there's no way it could work anyway.<script> blocks out of the asd.php that you are loading, and include any logic inside them in scripts loaded by content.php. Pass a completed-callback function() { // do asd stuff } to the load() method.Are you sure content loaded three times? Have you used firebug to watch what is actually transfered?
