JSON Exception: java.lang.String cannot be converted to JSONObject

Question

I'm having a JSON Exception being thrown and I don't know why it is being thrown. I've taken a look at almost all of the other questions that are just like mine, but I think mine is different. So I am getting a JSONArray from a webpage, and the JSON it sends is valid (I checked it with a validator). The exception is being thrown when I perform getJSONObject on the JSONArray.

Here's exactly what it says (personal information is starred out):

org.json.JSONException: Value  [{"name":"*****","profilePicture":"*****"}] at 0 of type java.lang.String cannot be converted to JSONObject

And here's my Java code:

 protected Void doInBackground(JSONObject... params) {
        JSONObject jsonObject = params[0];
        ClientServerInterface clientServerInterface = new ClientServerInterface();
        JSONArray attendanceDetails = clientServerInterface.postData("http://54.164.136.46/get_attendance.php", jsonObject);
        Log.e("Attendance Details: ", attendanceDetails.toString());

        nameAttendees = new String[attendanceDetails.length()];
        pictureAttendees = new String[attendanceDetails.length()];

        JSONObject jobj = null;
 for(int i = 0; i < attendanceDetails.length(); i++)
        {
            try {
                jobj = attendanceDetails.getJSONObject(i);
                nameAttendees[i] = jobj.getString("name");
                pictureAttendees[i] = jobj.getString("profilePicture");
            } catch (JSONException e) {
                e.printStackTrace();
            }

The error is happening at the line where I go:

jobj = attendanceDetails.getJSONObject(i);

Any help is greatly appreciated.

This code seem correct. Can you post few more line above the for loop? — Rohit5k2
– Rohit5k2, Commented Feb 4, 2015 at 2:40
Can you post the JSON you are trying to parse? It looks like the element you try to parse is a string ["name"] while you are expecting an object [{"name": "name"}] — hidro
– hidro, Commented Feb 4, 2015 at 2:43
Oh I see something strange. I printed out the JSONArray and here is what it is: [" [{\"name\":\"*****\",\"profilePicture\":\"*****\"}]\n"] — Kartik Prabhu
– Kartik Prabhu, Commented Feb 4, 2015 at 2:50

fyales · Accepted Answer · 2015-02-04 03:52:32Z

1

Try this:

for(int i = 0; i < attendanceDetails.length(); i++)
    {
        try {
            JSONArray hello = new JSONArray(attendanceDetails.getJSONArray(i));
            JSONObject jObject = new  JSONObject(hello.get(i).toString());
            nameAttendees[i] = jObject.getString("name");
            pictureAttendees[i] = jObject.getString("profilePicture");
        } catch (JSONException e) {
            e.printStackTrace();
        }

edited Feb 4, 2015 at 3:52

answered Feb 4, 2015 at 3:04

fyales

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11 Comments

Kartik Prabhu Over a year ago

The variable jobj is of type JSONObject. So should I cast it to JSONObject, since .get returns type Object?

Kartik Prabhu Over a year ago

Now I'm getting this exception: java.lang.String cannot be cast to org.json.JSONObject

fyales Over a year ago

You can't.when you use get function.You can get a String in your example .though the String is a object.It can's convert to JSONObject,unless it is a real object instead of subclass of object.

Kartik Prabhu Over a year ago

Here's what I did:

JSONObject jObject =  new JSONObject(attendanceDetails.get(i).toString());                     nameAttendees[i] = jObject.getString("name");                     pictureAttendees[i] = jObject.getString("profilePicture");

And error is JSONArray cannot be converted into JSONObject

fyales Over a year ago

JSONArray hello = new JSONArray(attendanceDetails.getJSONArray(i));JSONObject jObject = new JSONObject(hello.get(i).toString());

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