The code in PHP using the exec() command looks like this:
exec('javac -classpath dir test.java');
I am wondering how I can catch syntax errors that exist within the test.java file.
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1By compiling test.java probablySterling Archer– Sterling Archer2015-02-04 15:44:35 +00:00Commented Feb 4, 2015 at 15:44
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If you can get what would otherwise be printed to the console, that's what you want. You should give us an example of what you've tried so far and an example of what you mean, so you get better answers.anon– anon2015-02-04 15:58:27 +00:00Commented Feb 4, 2015 at 15:58
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2 Answers
You need to redirect stderr to stdout.
Append 2>&1 to the end of your command
exec('javac -classpath dir test.java 2>&1',$op);
var_dump($op);
Here 2 is stderr and 1 is stdout
Comments
If you use all 3 exec arguments, you'll see the output:
from http://php.net/manual/en/function.exec.php
string exec ( string $command [, array &$output [, int &$return_var ]] )
exec() executes the given command.
Parameters ¶
command
The command that will be executed.
output
If the output argument is present, then the specified array will be filled with every line of output from the command. Trailing whitespace, such as \n, is not included in this array. Note that if the array already contains some elements, exec() will append to the end of the array. If you do not want the function to append elements, call unset() on the array before passing it to exec().
return_var
If the return_var argument is present along with the output argument, then the return status of the executed command will be written to this variable.
