set images url to background attribute using concatenation

Question

What's wrong with my concatenation below?

$(function(){

    var bg = "http://i.imgur.com/kqRNO6M.jpg";
    var html = '<div style="background:linear-gradient(rgba(0, 0, 0, 0.35), rgba(0, 0, 0, 0.35)),url(\"'+ bg +'\") no-repeat;">';
});

my demo is here http://jsfiddle.net/su3fpkex/

I escaped double quote with \ but couldn't seem working.

I'm confused...you set some variables then don't do anything with them? — Paulie_D
– Paulie_D, Commented Feb 5, 2015 at 13:44

rvandoni · Accepted Answer · 2015-02-05 13:45:42Z

2

try with this:

$(function(){

  var bg = "http://i.imgur.com/kqRNO6M.jpg";
  var html = '<div style=\'background:linear-gradient(rgba(0, 0, 0, 0.35), rgba(0, 0, 0, 0.35)),url("'+ bg +'") no-repeat;\'>';

});

and remember to append somewhere your html variable! :)

answered Feb 5, 2015 at 13:45

rvandoni

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3 Comments

rvandoni Over a year ago

sure, you have to use your "html" variable in one way or another :D it's just to explain how to concatenate correctly these strings :)

Fernandez Over a year ago

this work but i don't understant the concatenation here, why escpae from the beginning?

rvandoni Over a year ago

if you escape the ' when specifying attributes you can use plain quotes inside the string. I prefer this way :)

MarcoL · Accepted Answer · 2015-02-05 14:49:36Z

1

You forgot to put the html content in the page:

$(function(){

    var bg = "http://i.imgur.com/kqRNO6M.jpg";
    var html = '<div style="background:linear-gradient(rgba(0, 0, 0, 0.35), rgba(0, 0, 0, 0.35)),url(\''+ bg +'\') no-repeat;">';
    $('body').append(html);
});

edited Feb 5, 2015 at 14:49

MarcoL

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answered Feb 5, 2015 at 13:57

Gilson PJ

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Comments

dam660 · Accepted Answer · 2015-02-05 13:45:34Z

0

Try this

$(function(){

    var bg = "http://i.imgur.com/kqRNO6M.jpg";
    var html = '<div style="background:linear-gradient(rgba(0, 0, 0, 0.35), rgba(0, 0, 0, 0.35)),url(\''+ bg +'\') no-repeat;">';

    alert(html);
});

answered Feb 5, 2015 at 13:45

dam660

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Comments

Dileep · Accepted Answer · 2015-02-05 14:10:25Z

0

If you set background image you have to set width and height for div.

<div class='img'></div>

$(function(){
   var bg = "http://i.imgur.com/kqRNO6M.jpg";
   var html = '<div style="width:300px;height:300px;background-size:cover;background:linear-gradient(rgba(0, 0, 0, 0.35), rgba(0, 0, 0, 0.35)),url(\''+ bg +'\') no-repeat;">';
    $('.img').html(html);

});

answered Feb 5, 2015 at 14:10

Dileep

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