Adding array to an object breaks the array

Question

I have an array like this (output from print_r):

Array
(
    [price] => 700.00
    [room_prices] => Array
        (
            [0] => 
            [1] => 
            [2] => 
            [3] => 
            [4] => 
        )

    [bills] => Array
        (
            [0] => Gas
        )
)

I'm running a custom function to convert it to an object. Only the top-level should be converted, the sub-arrays should stay as arrays. The output comes out like this:

stdClass Object
(
    [price] => 700.00
    [room_prices] => Array
        (
            [0] => Array
        )

    [bills] => Array
        (
            [0] => Array
        )
)

Here is my conversion function. All it does is set the value of each array member to an object:

function array_to_object( $arr )
{
    $obj = new stdClass;
    if ( count($arr) == 0 )
        return $obj;

    foreach ( $arr as $k=>$v )
        $obj->$k = $v;

    return $obj;
}

I can't figure this out for the life of me!

ax. · Accepted Answer · 2010-05-14 15:30:42Z

4

why don't you just cast the array to an object?

$myObj = (object) $myArray;

answered May 14, 2010 at 15:30

ax.

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Comments

Artefacto · Accepted Answer · 2010-05-14 15:24:37Z

3

I can't reproduce (PHP 5.3):

$a = array(
    "price" =>  700.00,
    "room_price" => array(NULL, NULL, NULL, NULL, NULL),
    bills => array("Gas"),
);

function array_to_object( $arr )
{
    $obj = new stdClass;
    if ( count($arr) == 0 )
        return $obj;

    foreach ( $arr as $k=>$v )
        $obj->$k = $v;

    return $obj;
}

print_r(array_to_object($a));

gives

stdClass Object
(
    [price] => 700
    [room_price] => Array
        (
            [0] =>
            [1] =>
            [2] =>
            [3] =>
            [4] =>
        )

    [bills] => Array
        (
            [0] => Gas
        )

)

answered May 14, 2010 at 15:24

Artefacto

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1 Comment

DisgruntledGoat Over a year ago

Thanks for the response. I checked the output right after the function and realised the function is working correctly! There was another part of my code modifying the output afterwards. One of those faceslap moments.

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