how to a php function which does not parameters from ajax?

Question

I have js function to call a php function via ajax.

$("#history").click(function(){
    $.ajax({
        url: "./function.php",
        type: "POST",
        data: {"displayBookingHistory"},
        dataType: "JSON",
        success: function(data) { 
            console.log("hellosdasdasds");
            $("#universalLogin").append(data);
        }
    }); 
})

and php function is

function displayBookingHistory () {
    $html = " ";
    ....
    echo json_encode($html);
}

and the call seems to be not successful, even when I try data: "displayBookingHistory",

Anyone knows solutions?

Try "return json_encode($html);" instead of "echo json_encode($html);". The data you submit isn't a function in PHP, it's the data you can work with in your PHP script. To call the function you have to add additional infos to the URL. — stefan
– stefan, Commented Feb 8, 2015 at 11:32

Quentin · Accepted Answer · 2015-02-08 11:34:07Z

2

You have a syntax error in your JavaScript: an object needs to consist of a series of property:value pairs.
You can't call a PHP function using Ajax. Only a URL. You need to write your PHP so that it calls the function if you hit that URL.
You are completely ignoring $_POST in your PHP, so there is no reason for it to do anything with the data you are sending to it.

answered Feb 8, 2015 at 11:34

Quentin

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Comments

ReallyMadeMeThink · Accepted Answer · 2015-02-08 11:41:02Z

jQuery's AJAX method expects an object with key:value pairs (or a string) for the data field.

Like Quentin said you can't call PHP functions from AJAX, only complete pages. If you want to communicate "run this function" you will have to use $_POST data like this:

$("#history").click(function(){
    $.ajax({
        url: "./function.php",
        type: "POST",
        data: {function:"displayBookingHistory"},
        dataType: "JSON",
        success: function(data) { 
            console.log("hellosdasdasds");
            $("#universalLogin").append(data);
        }
    }); 
})

Then in your PHP page:

if(isset($_POST["function"]){
    $function = $_POST["function"];
    if($function=="displayBookingHistory"){
        displayBookingHistory();
    }
}

vamshi mutyala · Accepted Answer · 2015-02-08 11:38:39Z

0

How are you invoking that function? May be you should have a switch statement that will check the data and call that function. something like this

 if(isset($_POST[data]){
 switch($_POST[data]){
 case "displayBookingHistory" : 
  displayBookingHistory();
 break;
 }
}

answered Feb 8, 2015 at 11:38

vamshi mutyala

111 bronze badge

Comments

Farhang Negari · Accepted Answer · 2015-02-08 12:39:37Z

your have syntax error ajax send data.

data : {"property:value"} or data : {"property:value" , "property:value" , ...}

problem can be solved in 2 ways:

$ ("# history"). click (function () {
     $ .ajax ({
         url: "/function.php?action=displayBookingHistory",
         type: "POST",
         dataType: "JSON",
         success: function (data) {
             console.log ("hellosdasdasds");
             $ ("# universalLogin"). append (data);

             return false; //for disable a tag (link) click;
         }
     });
})

"action" is a parameter used for $_GET type to check php code.

Or

$ ("# history"). click (function () {
     $ .ajax ({
         url: "/function.php",
         type: "POST",
         data: {"action":"displayBookingHistory"},
         dataType: "JSON",
         success: function (data) {
             console.log ("hellosdasdasds");
             $ ("# universalLogin"). append (data);

             return false; //for disable a tag (link) click;
         }
     });
})

"action" is a parameter used for $_POST type to check php code.

the best way is read a tag href attribute for work in javascript disable.

a tag :

<a href="/function.php?action=displayBookingHistory" id="history">linke</a>

javascript :

$ ("# history"). click (function () {
     $ .ajax ({
         url: $(this).attr("href"),
         type: "POST",
         dataType: "JSON",
         success: function (data) {
             console.log ("hellosdasdasds");
             $ ("# universalLogin"). append (data);

             return false; //for disable a tag (link) click;
         }
     });
})

php code :

   $action = isset($_GET["action"]) ? $_GET["action"] : "";

   if($action == 'displayBookingHistory' )
       displayBookingHistory();

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